Backward for addition, Backward for multiplication and Backward for matmul each computed a LOCAL backward rule, given some upstream gradient, produce the gradient for each input, as a one-off function call. A real autograd engine needs more: it needs to remember, automatically, WHICH operations built which values, in what order, so that calling .backward() once, at the very end of a computation, can walk backward through every operation that happened and apply each one's local rule in the right order, without a human manually chaining the calls together.
This question builds the object that makes that possible: a graph NODE that doesn't just hold a number, it also remembers its own parents (what it was built from) and carries its own _backward function (how to push gradient into those parents), attached automatically the moment an operation creates it.
Theory wraps Backward for addition and Backward for multiplication's formulas into Value's __add__ and __mul__ operator overloads: each one builds a new Value recording its own parents, and attaches a _backward closure that, when called, applies that operation's backward formula and ACCUMULATES (not overwrites) gradient into each parent.
Implement Value.__add__ and Value.__mul__ against that reasoning. The class skeleton, __init__, and docstrings are already in the editor.
other may be a plain Python number, not just a Value, wrap it in Value(other) first.+=), never overwrite (=), a node used in more than one place needs contributions from every place it was used, added together.out._backward must be attached as a closure capturing self, other, and out (via Python's closure scoping, not passed as explicit arguments).Open one at a time. Each gives away a little more than the last.
Backward for addition's rule was (grad_output, grad_output); inside _backward, grad_output is simply out.grad (the parent's own accumulated gradient, set by whatever comes later).
Define _backward as a nested function INSIDE __add__/__mul__ (so it closes over self, other, out automatically), then assign it: out._backward = _backward.
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