You want to highlight users who are older than average. You cannot compare against AVG(age) directly in a WHERE clause, because the average has to be computed first.
Write a query returning id, name and age of every user whose age is strictly greater than the average age of all users. Use a subquery for the average.
id, name, ageA subquery is a SELECT in parentheses used as a value.
WHERE age > (SELECT AVG(age) FROM users)
No results yet
Run your code to check it against the examples, or submit to run every test.